In Verilog, how would the logical equality ==) and case equality ===) operators evaluate the comparison 4'b101x 4'b101z and 4'b101x = 4'b101z respectively?
4'b101x == 4'b101zResult: 1'bx (Unknown)
Why: The logical equality (==The operator is used for comparison in standard hardware logic. If any bit in either operand is x or z, The simulator cannot determine if the two values are truly equal or not. As a result, the entire comparison fails to resolve to a definitive true (1) or false (0) and instead returns x.
4'b101x === 4'b101zResult: 1'b0 (False)
Why: The case equality (===) operator performs a strict, literal, bit-by-bit match, including x and z states. It asks the question: "Are these two strings of bits exactly identical in every way?" Because the last bit of the first operand is x and the last bit of the second operand is z, they do not match. Therefore, it returns a definitive 0