A 2-input NAND gate has inputs A and B. If the probability of A being '1' is 0.6 and B being '1' is 0.5, what is the probability that the output is '0'?
A NAND gate output is '0' only if both inputs are '1'. Assuming inputs are independent, P(Out=0) = P(A=1) * P(B=1) = 0.6 * 0.5 = 0.3.
